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statistics - Random Variable Probability Russian Roulette - Mathematics ...
There are two types of Russian Roulette. Type (i): We always randomize (twirl the chamber) between shots, and Type (ii): We do not randomize. It is not clear what type the questioner has in mind, so we analyze each type. Type (i): This version is exactly like tossing a fair die until we get, say, a $5$. It is a version of sampling with replacement.
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probability - In Russian roulette, is it best to go first ...
1. For 2 players and n chambers player 1 loses if the round is in the odd-numbered chamber. Hence if n n is even, chances are 50/50 50 / 50 and if n is odd, chances of losing are (n+1 2n, n−1 2n (n + 1 2 n, n − 1 2 n) - it's a disadvantage to go first. Share.
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probability - Russian Roulette Game - Mathematics Stack Exchange
Apr 18, 2020 at 18:22. Note that by simple set arithmetic on the events, Ac 1 ∩ A2 and Ac 1 ∩ Ac 2 are a partition of Ac 1, so P(Ac 1) = P(Ac 1, A2) + P(Ac 1, Ac 2). So if you say P(Ac 1, Ac 2) = 0 then you are saying that P(Ac 1, A2) = P(Ac 1) = 1 6, that is, this is the probability that A dies in round 1 but survives round 2. – David K.
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Calculating probability and optimization - russian roulette
In a game of Russian Roulette, there are 6 chambers, one of which has a bullet in it. You are playing with one other person. You go first. Now, your chance of getting hit is 1/6. After firing (and not getting hit), you can either pull the trigger again (1/5 probability of getting hit), or you can pass the gun and let Player 2 try.
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Russian roulette statistics - Mathematics Stack Exchange
"You're playing a game of Russian roulette, the revolver has 6 chambers in which you put 3 bullets completely random. What is the probability that all bullets are next to each other?" The solution says 0.3. I have no clue how to start with this problem or which kind of distribution to choose. Can I get feedback on this problem? Thanks, Ter
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Russian roulette - probability with spinning - Mathematics Stack Exchange
Typical Russian Roulette question, but I can't get my head around it: 1 person has a gun with 1 bullet (6 chambers). He spins the chambers before every attempt. What are the odds that he WON'T survive 4 tries? The solution should be 0.8024, but I have no idea how to get to that result.
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probability - Russian roulette should a player pull the trigger or spin ...
Two men plays Russian roulette. In revolver there are 2 bullets in consecutive chambers( 2 bullets are in 2 chambers next to each other). One man spun the cylinder, pulled the trigger and he is fine, so the chamber was empty. What should the second man do: pull the trigger or spin the cylinder. My answer: Pull the trigger. Explanation:
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probability - Would going first in Egg Russian Roulette increase or ...
Egg Russian Roulette: 6 eggs, 5 of which are hard boiled & 1 of which is raw. Players (1v1) each choose eggs in a turn based system whereby the egg is smashed against the forehead. The first player to smash the raw egg against his/her forehead is the loser.
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Russian Roulette Probability Puzzle understanding
The implication being that we want to avoid shooting ourselves and the game will end immediately after the next time the trigger is pulled. If we weren't to spin again, we will shoot ourselves with probability Pr(A ∣ B) = 1 5 P r (A ∣ B) = 1 5. If we were to spin again we will shoot ourselves with probability 1 6 1 6 which is less than 1 5 1 5.
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Mean value in a russian roulette game - Mathematics Stack Exchange
Thus, the probability distribution P(X = n) can be found considering that: the player having played n turns means that he survided this n turns. This is the same probability as above and hence P(X = n) = pn. The mean value then becomes. X = ∞ ∑ n = 1nP(X = n) = ∞ ∑ n = 0npn = p d dp ∞ ∑ n = 0pn = p d dp 1 1 − p = p 1 (1 − p)2.
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